An object of mass 12 kg is at a certain height above the ground. If the potential energy of the object is 480 J, find the height at which the object is with respect to the ground. Given, g = 10 m s–2 .

Solution:
Mass of the object, m = 12 kg,
potential energy, Ep = 480 J.
Ep = mgh
480 J = 12 kg × 10 m s–2 × h
h = 480 J / 120 kg m s –2 = 4 m.
The object is at the height of 4 m.

Leave a Comment

Your email address will not be published.