**Solution**:

Mass of the car, m =1500 kg,

initial velocity of car, u = 30 km h^{–1}= 30 × 1000m / 60 × 60s

= 25/3 m s^{–1}

.

Similarly, the final velocity of the car,

v = 60 km h^{–1} = 50/3 m s^{–1}

.

Therefore, the initial kinetic energy of the car,

K E_{i }= 1/2 m u^{2}

= 1/2× 1500 kg × (25/3 m s^{–1})

= 156250/3 J.

The final kinetic energy of the car,

K E_{ f} = 1/2 × 1500 kg × (50/3 m s^{–1})

= 625000/3 J.

Thus, the work done = Change in kinetic energy

= KE_{i} – KE_{f} = 156250 J.